v^2+10v=5

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Solution for v^2+10v=5 equation:


Simplifying
v2 + 10v = 5

Reorder the terms:
10v + v2 = 5

Solving
10v + v2 = 5

Solving for variable 'v'.

Reorder the terms:
-5 + 10v + v2 = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + 10v + v2 = 0

Begin completing the square.

Move the constant term to the right:

Add '5' to each side of the equation.
-5 + 10v + 5 + v2 = 0 + 5

Reorder the terms:
-5 + 5 + 10v + v2 = 0 + 5

Combine like terms: -5 + 5 = 0
0 + 10v + v2 = 0 + 5
10v + v2 = 0 + 5

Combine like terms: 0 + 5 = 5
10v + v2 = 5

The v term is 10v.  Take half its coefficient (5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
10v + 25 + v2 = 5 + 25

Reorder the terms:
25 + 10v + v2 = 5 + 25

Combine like terms: 5 + 25 = 30
25 + 10v + v2 = 30

Factor a perfect square on the left side:
(v + 5)(v + 5) = 30

Calculate the square root of the right side: 5.477225575

Break this problem into two subproblems by setting 
(v + 5) equal to 5.477225575 and -5.477225575.

Subproblem 1

v + 5 = 5.477225575 Simplifying v + 5 = 5.477225575 Reorder the terms: 5 + v = 5.477225575 Solving 5 + v = 5.477225575 Solving for variable 'v'. Move all terms containing v to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + v = 5.477225575 + -5 Combine like terms: 5 + -5 = 0 0 + v = 5.477225575 + -5 v = 5.477225575 + -5 Combine like terms: 5.477225575 + -5 = 0.477225575 v = 0.477225575 Simplifying v = 0.477225575

Subproblem 2

v + 5 = -5.477225575 Simplifying v + 5 = -5.477225575 Reorder the terms: 5 + v = -5.477225575 Solving 5 + v = -5.477225575 Solving for variable 'v'. Move all terms containing v to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + v = -5.477225575 + -5 Combine like terms: 5 + -5 = 0 0 + v = -5.477225575 + -5 v = -5.477225575 + -5 Combine like terms: -5.477225575 + -5 = -10.477225575 v = -10.477225575 Simplifying v = -10.477225575

Solution

The solution to the problem is based on the solutions from the subproblems. v = {0.477225575, -10.477225575}

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